# QThe length of stay (in hours) for a sample of 12 pneumonia patients at Santa Theresa Memorial Hospital was found to have a mean of 126 hours and a standard deviation of 21.663 hours

The length of stay (in hours) for a sample of 12 pneumonia patients at Santa Theresa Memorial Hospital was found to have a mean of 126 hours and a standard deviation of 21.663 hours. Find the 90 percent confidence interval on the standard deviation of the length of stay.

## 1 answers

This question still have no answer summary yet.
#1ThanhAnswered at 2013-02-24 10:34:43
The length of stay (in hours) for a sample of 12 pneumonia patients at Santa Theresa Memorial Hospital was found to have a mean of 126 hours and a standard deviation of 21.663 hours. Find the 90 percent confidence interval on the standard deviation of the length of stay. --- sample mean = 126 margin of error = 1.645*21.663/sqrt(12) = 10.29 --- 90%CI: 126-10.29 < u < 126+10.29 ============ Cheers, Stan H. ============
Anonymous
Add Answer of
The length of stay (in hours) for a sample of 12 pneumonia patients at Santa Theresa Memorial Hospital was found to have a mean of 126 hours and a standard deviation of 21.663 hours

Did this answer your question? If not, ask a new question.