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QThe cooling system on a truck contains 5 gallons of collant that is 40% antifreeze mixture

The cooling system on a truck contains 5 gallons of collant that is 40% antifreeze mixture. How much must be withdrawn and replaced with pure 100% antifreeze to bring the coolant in the system to a 50% antifreeze mixture?

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#1Need Help With EnglishAnswered at 2013-03-04 18:52:28
The cooling system on a truck contains 5 gallons of collant that is 40% antifreeze mixture. How much must be withdrawn and replaced with pure 100% antifreeze to bring the coolant in the system to a 50% antifreeze mixture? -------------------------------- Equation: anti -anti + anti = anti 0.40*5 - 0.40x + x = 0.50(5) Multiply thru by 100 to get: 40*5 - 40x + 100x = 50*5 60x = 10*5 x = (1/6)5 = 5/6 gallon (amt. that should be replaced in the mixture) ====================================================================== Cheers, stan H. ================================================
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