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QA chemist has a 30% saline solution and a 55% saline solution available

A chemist has a 30% saline solution and a 55% saline solution available. How many milliliters of each of these available solutions should she mix to obtain 700 ml of a 40% solution?

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#1kgAnswered at 2013-03-11 13:36:07
A chemist has a 30% saline solution and a 55% saline solution available. How many milliliters of each of these available solutions should she mix to obtain 700 ml of a 40% solution? . Let x = amount (ml) of 30% solution then 700-x = amount (ml) of 55% solution . .30x + .55(700-x) = .40(700) .30x + 385 - .55x = 280 385 - .25x = 280 -.25x = -105 x = 420 ml (30% saline) . 55% saline: 700-x = 700-420 = 280 ml
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