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QHow many gallons of a 60% antifreeze solution must be mixed with 90 gallons of 10% antifreeze to get a mixture that is 50% difference

How many gallons of a 60% antifreeze solution must be mixed with 90 gallons of 10% antifreeze to get a mixture that is 50% difference?

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#1kitsyAnswered at 2013-03-13 18:39:31
How many gallons of a 60% antifreeze solution must be mixed with 90 gallons of 10% antifreeze to get a mixture that is 50% difference? . Let x = amount (gallons) of 60% antifreeze then .60x + .10(90) = .50(x+90) .60x + 9 = .50x+45 .10x + 9 = 45 .10x = 36 x = 360 gallons
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How many gallons of a 60% antifreeze solution must be mixed with 90 gallons of 10% antifreeze to get a mixture that is 50% difference

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