A FLORIST PLACED AN ADVERTISEMENT IN THE NEWSPAPER. THE NEXT WEEK THE FLORIST REPLACED THE ORIGINAL ADVERTISEMENT WITH A NEW ONE, BUT THE LENGTH AND WIDTH OF THENEW ADVERTISEMENT WERE 1/2 THE ORIGINAL. HOW MUCH GREATER IS THE AREA OF THE ORIGINAL ADVERTISEMENT THAN THE REPLACED ADVERTISEMENT?

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lets say that the length is 'L' and the width is 'W'

Area of original = L*W

Now the length is '.5L' and the width is '.5W'

Area of new ad = (.5L)(.5W) = .25LW

The new area is 1/4 of the original.

Area of original = L*W

Now the length is '.5L' and the width is '.5W'

Area of new ad = (.5L)(.5W) = .25LW

The new area is 1/4 of the original.

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