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QHere is the question: A metal cube of volume 1000cm^3 is melted down and cast into a cuboid 50cm long and 10cm broad

Here is the question: A metal cube of volume 1000cm^3 is melted down and cast into a cuboid 50cm long and 10cm broad. What is the percentage increase in the surface areas of the solids?

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#1SerrenaAnswered at 2014-02-02 20:31:39
{{{V = 1000}}} cm2 {{{V = s^3}}} where {{{s}}} is the length of all the sides {{{V = 10*10*10}}} cm2 {{{s = 10}}}cm The surface area is {{{A[1] = 6*10*10}}}cm2 {{{A[1] = 600}}}cm2 ---------------------- {{{50*10*s = 1000}}} Even though the dimensions change, V can't change {{{s = 1000/500}}} {{{s = 2}}} {{{50*10*2 = 1000}}} Two of the faces are {{{50*10}}}cm2 Two of the faces are {{{50*2}}}cm2 Two of the faces are {{{2*10}}} cm2 {{{A[2] = 2*50*10 + 2*50*2 + 2*2*10}}} {{{A[2] = 1000 + 200 + 40}}} {{{A[2] = 1240}}} The increase in area is {{{A[2] - A[1] = 1240 - 1000}}}cm2 {{{1240 - 1000 = 240}}}cm2 The percentage increase is {{{240/1000}}} = 24% answer
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Here is the question: A metal cube of volume 1000cm^3 is melted down and cast into a cuboid 50cm long and 10cm broad

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