Homework Help


QHow much energy does it extract from the outside air with coefficient of performance 3.85

How much energy does it extract from the outside air with coefficient of performance 3.85?
A heat pump has a coefficient of performance of 3.85 and operates with a power consumption of 6.91 x 10^3 W.

The first part of the question asked How much energy does it deliver into a home during 8 h of continuous operation? and I got 766180800 J.

I need help on the last part which asks How much energy does it extract from the outside air? answer in Joules.
This question still have no answer summary yet.
2 answers.
#1PickleAnswered at 2012-10-13 21:08:12
I got lost when you got to:

= Qout - Qout/3.85
= 0.7403 Qout

What did you exactly do? I'm not seeing where those two Qout's came from and how you got the .7403.
#2Shaz.EAnswered at 2013-01-06 09:05:44
Qout = Qin + Win

Qin = Qout - Win
= Qout - Qout/3.85
= 0.7403 Qout

Use your previously caclulated value of Qout, which was correct. Scientific notation would be preferable
Anonymous Sign In Sign Up
Add Answer of
How much energy does it extract from the outside air with coefficient of performance 3.85

Did this answer your question? If not, ask a new question.

Related Answers