- 1I need help with semester exam review.
The graph of the line with equation y= -400 is what line?

- 2(Semester Exam Unit 1!)
The sides of an equilateral triangle measure (2x + 4) units. What is the perimeter?

- 3(Semester Exam Unit 1!)
The sides of an equilateral triangle measure (2x + 4) units. What is the perimeter?

- 4Ok, so I'm trying to do this for my exam review
Ok, so I'm trying to do this for my exam review. I get some of it, but not all: An electric utility is examining the relationship between temperature and electricity use in its service region on warm days. The utility has bivariate data detailing the maximum temperature (denoted by x, in degrees Fahrenheit) and the electricity use (denoted by y, in thousands of kilowatt hours) for a random sample of 28 warm days. For these data, the utility has computed the least-squares regression equation to be yhat= 58.67+3.01x. Tomorrow's forecast high temperature is 80 degrees Fahrenheit. With this in mind, utility managers have used the regression equation to predict tomorrow's electricity use, but they're also interested in both a prediction interval for the electricity use and a confidence interval for the mean electricity use on days for which the maximum temperature is 80 degrees Fahrenheit. The managers have computed the following for their data: mean square error (MSE):776.23 some confidence interval expression:.0516 You then have to find the lower and upper limit with a 95% confidence interval.I know the formula is to find t.05(26)=1.706.Then its (1.706)(sqrt776.23)(sqrt.0516) My first problem is, it always .0516, because I thought you added 1 sometimes? The problem goes on to ask: Consider but do not actually compute the 95% confidence interval for the mean electricity use when the max temp is 80 degrees. how would the confidence interval compare to the prediction interval computed before? I'm lost hear. Then:For the maximum temp values in this sample, 71 degrees is more extreme than 81 degrees, that is, 71 is farther from the sample mean than 80. How would the 95% confidence interval for the mean electricity use when the maximum temp is 80 degrees compare to the 95% confidence interval for the mean electricity use when the temp is 71 degrees? I know it looks like alot, but I really need help and there's not even math involved.Thanks so much.

- 5Review exam 1
if F = 59 degree Fahrenheit then find the temperature in degree in Celsius?

- 6Exam 1 Review
1. Use the definition of a derivative to find the derivative of f(x) = 2x2 + 3x - 4Use Difference quotient and take the limit.2. Find the limit if it Exists (a, b, and c)3. Identify the conditions of continuity that are not satisfied for each point of discontinuity. Describe intervals ofcontinuity.a) points:Top left = (-2,1) Top Right = (3,1), Bottom Right = (3,-1)b) points: Top = (-2,6)4. Find each of the derivativesf ' (x) = y = f(x)in eacha) y = f(x) = 3x2 + 2x - 6b) f(x) = c) (x2 + 3x + 2) (x3 + 2x + 1) = f(x)d) f(x) = e) 5. Use implicit Differentiation to find the following derivative(s) for f(x)a) y2 + x2 = 36b) (x+y)3 = x3+ y3c) 2xy3- x3 = 66. Find the equation of the tangent liney= 12x1/3-2xat(8, -1)

- 7Ok, so I'm trying to do this for my exam review
Ok, so I'm trying to do this for my exam review. I get some of it, but not all: An electric utility is examining the relationship between temperature and electricity use in its service region on warm days. The utility has bivariate data detailing the maximum temperature (denoted by x, in degrees Fahrenheit) and the electricity use (denoted by y, in thousands of kilowatt hours) for a random sample of 28 warm days. For these data, the utility has computed the least-squares regression equation to be yhat= 58.67+3.01x. Tomorrow's forecast high temperature is 80 degrees Fahrenheit. With this in mind, utility managers have used the regression equation to predict tomorrow's electricity use, but they're also interested in both a prediction interval for the electricity use and a confidence interval for the mean electricity use on days for which the maximum temperature is 80 degrees Fahrenheit. The managers have computed the following for their data: mean square error (MSE):776.23 some confidence interval expression:.0516 You then have to find the lower and upper limit with a 95% confidence interval.I know the formula is to find t.05(26)=1.706.Then its (1.706)(sqrt776.23)(sqrt.0516) My first problem is, it always .0516, because I thought you added 1 sometimes? The problem goes on to ask: Consider but do not actually compute the 95% confidence interval for the mean electricity use when the max temp is 80 degrees. how would the confidence interval compare to the prediction interval computed before? I'm lost hear. Then:For the maximum temp values in this sample, 71 degrees is more extreme than 81 degrees, that is, 71 is farther from the sample mean than 80. How would the 95% confidence interval for the mean electricity use when the maximum temp is 80 degrees compare to the 95% confidence interval for the mean electricity use when the temp is 71 degrees? I know it looks like alot, but I really need help and there's not even math involved.Thanks so much.

- 8Geometry Exam Review Help
I'm taking my Exams soon and need help with the following on my review guide:1.State the law of detachment2. What is inductive reasoning?3.What is Deductive reasoning?Any help would be appreciated. (Also if anyone was wondering this review guide I'm am asking questions about is not graded so you are not helping me cheat or anything.I just have to make that clear.)

- 9Help with probability review for exam
Juan makes a measurement in a chemistry laboratory and records the result in his lab report. The standard deviation of students’ lab measurements is σ = 10milligrams. Juan repeats the measurement 3 times and records the mean x of his 3 measurements.(a) What is the standard deviation of Juan’s mean result? (That is, if Juan kept on making 3 measurements and averaging them, what would be the standard deviationof all his x’s?)

- 10On the semester exam in history, sally missed 5 questions on part A. Part B had
On the semester exam in history, sally missed 5 questions on part A. Part B had the same number of questions as part A but sally didn't do so well on part B. She missed 1/3 of the questions. Sally's overall score was 75%. How many questions were on the exam?...

- 11Help for the EXAM REVIEW, WILL RATE as I high as I can,
You are a photographer! You stand atth origin with your camera and your classmates are stung out alongy = e-x from (0,1) to(2, e-2)(a) As a function of X, What is your distance to yourclassmates at a point (x,y) on the curve?(b) Write down an integral that gives the average value ofthe function in (a).(c) you focus your camera according to your answer in part(b) Who is more in focus, the person at (0,1) or the person at (2,e-2) ?(d) Approximately where on the curve should you tell yourbest friend to stand so that she will be in focus?( solvefor her x coordinate)

- 12Need urgent help with this exam review question plz!!
The grandfather clock in the physics department is wound onceper week by raising a 6.7 kg brass cylinder 1.2 m using a crankthat is 4.2 cm long.a. how much potential energy is stored in the clock rightafter it is wound?b. what is the average power loss of the clock through theweek?Thanks in advance!